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| Enthalpy | |
| The enthalpy of a reaction is a measure of how much heat is absorbed or given
off when a chemical reaction takes place. It is represented by
ΔHrxn and is found by subtracting the enthalpy of the
reactants from the enthalpy of the products: ΔHrxn = ΣΔHproducts – ΣΔHreactants |
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The Greek letter
sigma,
Σ, may be new to you.
In mathematics, it is used to represent the phrase “to sum.” Therefore, this equation is telling us to sum the enthalpy of the products and subtract the sum of the enthalpy of the reactants. You should turn use your handbook to find the table labeled “Standard Thermodynamic Values at 25°C.” You will notice that the table, which covers many pages, has five columns. The first column is the formula of an element or compound you are looking up. The second column is its state of matter – which is very important. The third column lists ΔHformation values, or the enthalpy of formation. This is the amount of energy needed to form one mole of that compound. Most values as you can see are negative because releasing energy (exothermic) is a more common process in nature. Find sodium sulfide, or Na2S. As you can see, its enthalpy of formation is -373.2128 kJ/mol. This means that when one mole of sodium sulfide is formed from its constituent elements (sodium and sulfur), -373.2128 kilojoules of energy is released. Elements in their free state at their state of matter at 25°C (this is called the “standard state”) are assigned a value of 0.0. This is because elements are not formed from anything more basic, therefore no energy must be absorbed or released to create them. When the enthalpy of reaction is calculated, a negative value indicates the reaction is exothermic. A positive value indicates the reaction is endothermic. |
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| The reaction between sodium peroxide and zinc, using water as a catalyst, is highly exothermic. | |
| Entropy | |
The entropy of a reaction, or ΔSrxn,
is a measure of the disorder created by a reaction. There are two key ways to
increase the disorder of a reaction:
The entropy of a reaction can be calculated using a formula similar to the enthalpy of reaction: ΔSrxn = ΣΔSproducts – ΣΔSreactants |
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| The decomposition of mercury (II) oxide creates positive entropy, because there are more moles of product than reactant and a liquid and gas are produced from a solid. | |
| Gibbs Free Energy |
| Gibbs Free Energy is a quantity used to measure the amount of available energy
(to do work) that a chemical reaction provides. Furthermore, it can be used to
determine whether or not a reaction is spontaneous (works) at a given Kelvin
temperature. Reactions are very temperature dependent, and sometimes work
significantly better at some temperatures than others. The
ΔGrxn values provided in the
table are only viable at 25ºC (298.15 K). For all temperatures, including 25ºC,
the following equation can be used: ΔGrxn = ΔHrxn – TΔSrxn In order to use this equation properly, keep these thoughts in mind:
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| Videos |
| Click here to view videos of different chemical reactions. You can visually identify reactions that are exothermic or endothermic, create more or less disorder, or are spontaneous. |
| The Relationship between Spontaneity and the Sign of Enthalpy and Entropy Values | ||
| Consider the following table below: | ||
| + ΔS | - ΔS | |
| + ΔH | ΔG could be positive or negative. However, the reaction will be most favorable at lower temperatures. | ΔG is always negative. The reaction will not work at any temperature. |
| - ΔH | ΔG is always positive. The reaction will work at any temperature. | ΔG could be positive or negative. However, the reaction will be most favorable at higher temperatures. |
| Graphing Free Energy as a Function |
| Upon inspection, the equation ΔGrxn = ΔHrxn – T ΔSrxn can be proven to represent a linear function, where ΔGrxn is calculated over a series of temperatures while ΔHrxn and ΔSrxn remain constant. Recall the equation y = mx + b represents a linear equation, where each variable corresponds to a variable in ΔGrxn = ΔHrxn – T ΔSrxn. Rewriting the free energy equation as ΔGrxn = – T ΔSrxn + ΔHrxn makes it easier to see the parallel. Despite the position of T, it is not the slope of the equation. Since the slope must be constant, ΔSrxn will represent m or the slope. Since x is allowed to fluctuate (as is the temperature) T corresponds to x. This leaves ΔHrxn, which must correspond to b or the y-intercept of the equation. This can be used for determining a range of temperatures for which a reaction will be spontaneous or not. Realize this will work over a small temperature range since ΔS will change considerably over a large temperature range. |
| Example Problem |
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2 C2H6 (g) + 7 O2 (g) → 4 CO2 (g) + 6 H2O (g) at 300 degrees Celsius ΔHrxn = ΣΔHproducts – ΣΔHreactants
[4(-393.5) + 6(-241.8)] – [-84.0 + 7(0.0)] -3024.8 – -84.0 -2940.0 kJ → exothermic (because enthalpy is negative) Note that the equation can now be rewritten showing the enthalpy value as a product, because heat is being produced:2 C2H6 (g) + 7 O2 (g) → 4 CO2 (g) + 6 H2O (g) + 2940.0 kJ ΔSrxn = ΣΔSproducts – ΣΔSreactants
[4(213.8) + 6(188.8)] – [229.2 + 7(205.2)] 1988.0 – 1665.6 322.4 J/K → creates disorder (because entropy is positive)ΔGrxn = ΔHrxn – T ΔSrxn -2940.0 – (573.15)(.3224)-3124.8 kJ → spontaneous at this temperature (because the free energy is negative) |
| Phase Changes |
| Enthalpy can be used to determine the energy needed to change the state of matter for a particular substance. Specifically, the energy needed to cause a solid/liquid phase change is called the enthalpy of fusion, ΔHfus. When a substance changes from a solid to liquid, energy must be absorbed in order to separate the particles. Consequently, a solid to liquid phase change is endothermic. Since the reverse process must occur for a liquid to solid phase change, that process is exothermic. The value for ΔHfus does not change, only its sign changes. A liquid to gas change, measured by the enthalpy of vaporization (ΔHvap), can be viewed similarly. To change a liquid to a gas, energy must be absorbed and the process is endothermic, hence a positive enthalpy value. Condensation is an exothermic process and the enthalpy value is negative. |
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| Last update: Friday, June 25, 2010 |